There were some persimmons and lemons in Container S and Container T. In Container S, the ratio of the persimmons to the number of lemons was 6 : 1. In Container T, the ratio of the number of persimmons to the number of lemons was 4 : 3. There were 2 times as many fruits in Container S as in Container T. After another 25 lemons were put into Container T, the ratio of the number of persimmons to the number of lemons in Container T became 1 : 2. How many fruits were there in Container S?

Container S		Container T
2x7 = 14 u		1x7 = 7 u
Persimmons	Lemons	Persimmons	Lemons
6x2	1x2	4	3
12 u	2 u	4 u	3 u

The total number of fruits in Container S is repeated.  Make the total number of fruits in Container S the same.  LCM of 2 and 7 is 14.

The total number of fruits in Container T at first is repeated.  Make the total number of fruits in Container T the same.  LCM of 1 and 7 is 7.

	Container S		Container T
	Persimmons	Lemons	Persimmons	Lemons
Before	12 u	2 u	4 u	3 u
Change				+ 25
After	12 u	2 u	1x4 = 4 u	2x4 = 8 u

Number of persimmons in Container T remains unchanged.  Make the number of persimmons in Container T the same.  LCM of 4 and 1 is 4.

Number of lemons put into Container T
= 8 u - 3 u
= 5 u

5 u = 25

1 u = 25 ÷ 5 = 5

Number of fruits in Container S
= 12 u + 2 u
= 14 u
= 14 x 5
= 70

Answer(s): 70