There were some starfruits and kiwis in Box Y and Box Z. In Box Y, the ratio of the starfruits to the number of kiwis was 11 : 1. In Box Z, the ratio of the number of starfruits to the number of kiwis was 5 : 3. There were 3 times as many fruits in Box Y as in Box Z. After another 85 kiwis were put into Box Z, the ratio of the number of starfruits to the number of kiwis in Box Z became 1 : 4. How many fruits were there in Box Z in the end?

Box Y		Box Z
3x8 = 24 u		1x8 = 8 u
Starfruits	Kiwis	Starfruits	Kiwis
11x2	1x2	5	3
22 u	2 u	5 u	3 u

The total number of fruits in Box Y is repeated.  Make the total number of fruits in Box Y the same.  LCM of 3 and 12 is 24.

The total number of fruits in Box Z at first is repeated.  Make the total number of fruits in Box Z the same.  LCM of 1 and 8 is 8.

	Box Y		Box Z
	Starfruits	Kiwis	Starfruits	Kiwis
Before	22 u	2 u	5 u	3 u
Change				+ 85
After	22 u	2 u	1x5 = 5 u	4x5 = 20 u

Number of starfruits in Box Z remains unchanged.  Make the number of starfruits in Box Z the same.  LCM of 5 and 1 is 5.

Number of kiwis put into Box Z
= 20 u - 3 u
= 17 u

17 u = 85

1 u = 85 ÷ 17 = 5

Number of fruits in Box Z in the end
= 5 u + 20 u
= 25 u
= 25 x 5
= 125

Answer(s): 125