There were some starfruits and lemons in Box S and Box T. In Box S, the ratio of the starfruits to the number of lemons was 5 : 1. In Box T, the ratio of the number of starfruits to the number of lemons was 5 : 3. There were 3 times as many fruits in Box S as in Box T. After another 34 lemons were put into Box T, the ratio of the number of starfruits to the number of lemons in Box T became 1 : 4. How many fruits were there in Box S?
Box S |
Box T |
3x8 = 24 u |
1x8 = 8 u |
Starfruits |
Lemons |
Starfruits |
Lemons |
5x4 |
1x4 |
5 |
3 |
20 u |
4 u |
5 u |
3 u |
The total number of fruits in Box S is repeated. Make the total number of fruits in Box S the same. LCM of 3 and 6 is 24.
The total number of fruits in Box T at first is repeated. Make the total number of fruits in Box T the same. LCM of 1 and 8 is 8.
|
Box S |
Box T |
|
Starfruits |
Lemons |
Starfruits |
Lemons |
Before |
20 u |
4 u |
5 u |
3 u |
Change |
|
|
|
+ 34 |
After
|
20 u
|
4 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of starfruits in Box T remains unchanged. Make the number of starfruits in Box T the same. LCM of 5 and 1 is 5.
Number of lemons put into Box T
= 20 u - 3 u
= 17 u
17 u = 34
1 u = 34 ÷ 17 = 2
Number of fruits in Box S
= 20 u + 4 u
= 24 u
= 24 x 2
= 48
Answer(s): 48