There were some chikoos and mangoes in Container B and Container C. In Container B, the ratio of the chikoos to the number of mangoes was 4 : 1. In Container C, the ratio of the number of chikoos to the number of mangoes was 3 : 2. There were 2 times as many fruits in Container B as in Container C. After another 16 mangoes were put into Container C, the ratio of the number of chikoos to the number of mangoes in Container C became 1 : 2. How many fruits were there in Container C in the end?

Container B		Container C
2x5 = 10 u		1x5 = 5 u
Chikoos	Mangoes	Chikoos	Mangoes
4x2	1x2	3	2
8 u	2 u	3 u	2 u

The total number of fruits in Container B is repeated.  Make the total number of fruits in Container B the same.  LCM of 2 and 5 is 10.

The total number of fruits in Container C at first is repeated.  Make the total number of fruits in Container C the same.  LCM of 1 and 5 is 5.

	Container B		Container C
	Chikoos	Mangoes	Chikoos	Mangoes
Before	8 u	2 u	3 u	2 u
Change				+ 16
After	8 u	2 u	1x3 = 3 u	2x3 = 6 u

Number of chikoos in Container C remains unchanged.  Make the number of chikoos in Container C the same.  LCM of 3 and 1 is 3.

Number of mangoes put into Container C
= 6 u - 2 u
= 4 u

4 u = 16

1 u = 16 ÷ 4 = 4

Number of fruits in Container C in the end
= 3 u + 6 u
= 9 u
= 9 x 4
= 36

Answer(s): 36