There were some pears and chikoos in Container H and Container J. In Container H, the ratio of the pears to the number of chikoos was 5 : 1. In Container J, the ratio of the number of pears to the number of chikoos was 5 : 3. There were 3 times as many fruits in Container H as in Container J. After another 49 chikoos were put into Container J, the ratio of the number of pears to the number of chikoos in Container J became 1 : 2. How many fruits were there in Container H?

Container H		Container J
3x8 = 24 u		1x8 = 8 u
Pears	Chikoos	Pears	Chikoos
5x4	1x4	5	3
20 u	4 u	5 u	3 u

The total number of fruits in Container H is repeated.  Make the total number of fruits in Container H the same.  LCM of 3 and 6 is 24.

The total number of fruits in Container J at first is repeated.  Make the total number of fruits in Container J the same.  LCM of 1 and 8 is 8.

	Container H		Container J
	Pears	Chikoos	Pears	Chikoos
Before	20 u	4 u	5 u	3 u
Change				+ 49
After	20 u	4 u	1x5 = 5 u	2x5 = 10 u

Number of pears in Container J remains unchanged.  Make the number of pears in Container J the same.  LCM of 5 and 1 is 5.

Number of chikoos put into Container J
= 10 u - 3 u
= 7 u

7 u = 49

1 u = 49 ÷ 7 = 7

Number of fruits in Container H
= 20 u + 4 u
= 24 u
= 24 x 7
= 168

Answer(s): 168