There were some passion fruits and oranges in Container M and Container N. In Container M, the ratio of the passion fruits to the number of oranges was 7 : 1. In Container N, the ratio of the number of passion fruits to the number of oranges was 5 : 3. There were 3 times as many fruits in Container M as in Container N. After another 63 oranges were put into Container N, the ratio of the number of passion fruits to the number of oranges in Container N became 1 : 2. How many fruits were there in Container N in the end?

Container M		Container N
3x8 = 24 u		1x8 = 8 u
Passion fruits	Oranges	Passion fruits	Oranges
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Container M is repeated.  Make the total number of fruits in Container M the same.  LCM of 3 and 8 is 24.

The total number of fruits in Container N at first is repeated.  Make the total number of fruits in Container N the same.  LCM of 1 and 8 is 8.

	Container M		Container N
	Passion fruits	Oranges	Passion fruits	Oranges
Before	21 u	3 u	5 u	3 u
Change				+ 63
After	21 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of passion fruits in Container N remains unchanged.  Make the number of passion fruits in Container N the same.  LCM of 5 and 1 is 5.

Number of oranges put into Container N
= 10 u - 3 u
= 7 u

7 u = 63

1 u = 63 ÷ 7 = 9

Number of fruits in Container N in the end
= 5 u + 10 u
= 15 u
= 15 x 9
= 135

Answer(s): 135