There were some starfruits and chikoos in Box T and Box U. In Box T, the ratio of the starfruits to the number of chikoos was 11 : 1. In Box U, the ratio of the number of starfruits to the number of chikoos was 5 : 3. There were 3 times as many fruits in Box T as in Box U. After another 170 chikoos were put into Box U, the ratio of the number of starfruits to the number of chikoos in Box U became 1 : 4. How many fruits were there in Box T?
Box T |
Box U |
3x8 = 24 u |
1x8 = 8 u |
Starfruits |
Chikoos |
Starfruits |
Chikoos |
11x2 |
1x2 |
5 |
3 |
22 u |
2 u |
5 u |
3 u |
The total number of fruits in Box T is repeated. Make the total number of fruits in Box T the same. LCM of 3 and 12 is 24.
The total number of fruits in Box U at first is repeated. Make the total number of fruits in Box U the same. LCM of 1 and 8 is 8.
|
Box T |
Box U |
|
Starfruits |
Chikoos |
Starfruits |
Chikoos |
Before |
22 u |
2 u |
5 u |
3 u |
Change |
|
|
|
+ 170 |
After
|
22 u
|
2 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of starfruits in Box U remains unchanged. Make the number of starfruits in Box U the same. LCM of 5 and 1 is 5.
Number of chikoos put into Box U
= 20 u - 3 u
= 17 u
17 u = 170
1 u = 170 ÷ 17 = 10
Number of fruits in Box T
= 22 u + 2 u
= 24 u
= 24 x 10
= 240
Answer(s): 240