There were some kiwis and passion fruits in Box P and Box Q. In Box P, the ratio of the kiwis to the number of passion fruits was 6 : 1. In Box Q, the ratio of the number of kiwis to the number of passion fruits was 4 : 3. There were 2 times as many fruits in Box P as in Box Q. After another 40 passion fruits were put into Box Q, the ratio of the number of kiwis to the number of passion fruits in Box Q became 1 : 2. How many fruits were there in Box Q in the end?
Box P |
Box Q |
2x7 = 14 u |
1x7 = 7 u |
Kiwis |
Passion fruits |
Kiwis |
Passion fruits |
6x2 |
1x2 |
4 |
3 |
12 u |
2 u |
4 u |
3 u |
The total number of fruits in Box P is repeated. Make the total number of fruits in Box P the same. LCM of 2 and 7 is 14.
The total number of fruits in Box Q at first is repeated. Make the total number of fruits in Box Q the same. LCM of 1 and 7 is 7.
|
Box P |
Box Q |
|
Kiwis |
Passion fruits |
Kiwis |
Passion fruits |
Before |
12 u |
2 u |
4 u |
3 u |
Change |
|
|
|
+ 40 |
After
|
12 u
|
2 u
|
1x4 = 4 u |
2x4 = 8 u |
Number of kiwis in Box Q remains unchanged. Make the number of kiwis in Box Q the same. LCM of 4 and 1 is 4.
Number of passion fruits put into Box Q
= 8 u - 3 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of fruits in Box Q in the end
= 4 u + 8 u
= 12 u
= 12 x 8
= 96
Answer(s): 96