There were some kiwis and pears in Container V and Container W. In Container V, the ratio of the kiwis to the number of pears was 3 : 1. In Container W, the ratio of the number of kiwis to the number of pears was 5 : 3. There were 2 times as many fruits in Container V as in Container W. After another 56 pears were put into Container W, the ratio of the number of kiwis to the number of pears in Container W became 1 : 2. How many fruits were there in Container V?

Container V		Container W
2x8 = 16 u		1x8 = 8 u
Kiwis	Pears	Kiwis	Pears
3x4	1x4	5	3
12 u	4 u	5 u	3 u

The total number of fruits in Container V is repeated.  Make the total number of fruits in Container V the same.  LCM of 2 and 4 is 16.

The total number of fruits in Container W at first is repeated.  Make the total number of fruits in Container W the same.  LCM of 1 and 8 is 8.

	Container V		Container W
	Kiwis	Pears	Kiwis	Pears
Before	12 u	4 u	5 u	3 u
Change				+ 56
After	12 u	4 u	1x5 = 5 u	2x5 = 10 u

Number of kiwis in Container W remains unchanged.  Make the number of kiwis in Container W the same.  LCM of 5 and 1 is 5.

Number of pears put into Container W
= 10 u - 3 u
= 7 u

7 u = 56

1 u = 56 ÷ 7 = 8

Number of fruits in Container V
= 12 u + 4 u
= 16 u
= 16 x 8
= 128

Answer(s): 128