There were some persimmons and lemons in Container T and Container U. In Container T, the ratio of the persimmons to the number of lemons was 7 : 1. In Container U, the ratio of the number of persimmons to the number of lemons was 5 : 3. There were 3 times as many fruits in Container T as in Container U. After another 51 lemons were put into Container U, the ratio of the number of persimmons to the number of lemons in Container U became 1 : 4. How many fruits were there in Container U in the end?

Container T		Container U
3x8 = 24 u		1x8 = 8 u
Persimmons	Lemons	Persimmons	Lemons
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Container T is repeated.  Make the total number of fruits in Container T the same.  LCM of 3 and 8 is 24.

The total number of fruits in Container U at first is repeated.  Make the total number of fruits in Container U the same.  LCM of 1 and 8 is 8.

	Container T		Container U
	Persimmons	Lemons	Persimmons	Lemons
Before	21 u	3 u	5 u	3 u
Change				+ 51
After	21 u	3 u	1x5 = 5 u	4x5 = 20 u

Number of persimmons in Container U remains unchanged.  Make the number of persimmons in Container U the same.  LCM of 5 and 1 is 5.

Number of lemons put into Container U
= 20 u - 3 u
= 17 u

17 u = 51

1 u = 51 ÷ 17 = 3

Number of fruits in Container U in the end
= 5 u + 20 u
= 25 u
= 25 x 3
= 75

Answer(s): 75