There were some kiwis and starfruits in Box W and Box X. In Box W, the ratio of the kiwis to the number of starfruits was 7 : 1. In Box X, the ratio of the number of kiwis to the number of starfruits was 5 : 3. There were 3 times as many fruits in Box W as in Box X. After another 60 starfruits were put into Box X, the ratio of the number of kiwis to the number of starfruits in Box X became 1 : 3. How many fruits were there in Box W?
Box W |
Box X |
3x8 = 24 u |
1x8 = 8 u |
Kiwis |
Starfruits |
Kiwis |
Starfruits |
7x3 |
1x3 |
5 |
3 |
21 u |
3 u |
5 u |
3 u |
The total number of fruits in Box W is repeated. Make the total number of fruits in Box W the same. LCM of 3 and 8 is 24.
The total number of fruits in Box X at first is repeated. Make the total number of fruits in Box X the same. LCM of 1 and 8 is 8.
|
Box W |
Box X |
|
Kiwis |
Starfruits |
Kiwis |
Starfruits |
Before |
21 u |
3 u |
5 u |
3 u |
Change |
|
|
|
+ 60 |
After
|
21 u
|
3 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of kiwis in Box X remains unchanged. Make the number of kiwis in Box X the same. LCM of 5 and 1 is 5.
Number of starfruits put into Box X
= 15 u - 3 u
= 12 u
12 u = 60
1 u = 60 ÷ 12 = 5
Number of fruits in Box W
= 21 u + 3 u
= 24 u
= 24 x 5
= 120
Answer(s): 120