There were some oranges and persimmons in Box U and Box V. In Box U, the ratio of the oranges to the number of persimmons was 6 : 1. In Box V, the ratio of the number of oranges to the number of persimmons was 5 : 2. There were 3 times as many fruits in Box U as in Box V. After another 56 persimmons were put into Box V, the ratio of the number of oranges to the number of persimmons in Box V became 1 : 2. How many fruits were there in Box V in the end?

Box U		Box V
3x7 = 21 u		1x7 = 7 u
Oranges	Persimmons	Oranges	Persimmons
6x3	1x3	5	2
18 u	3 u	5 u	2 u

The total number of fruits in Box U is repeated.  Make the total number of fruits in Box U the same.  LCM of 3 and 7 is 21.

The total number of fruits in Box V at first is repeated.  Make the total number of fruits in Box V the same.  LCM of 1 and 7 is 7.

	Box U		Box V
	Oranges	Persimmons	Oranges	Persimmons
Before	18 u	3 u	5 u	2 u
Change				+ 56
After	18 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of oranges in Box V remains unchanged.  Make the number of oranges in Box V the same.  LCM of 5 and 1 is 5.

Number of persimmons put into Box V
= 10 u - 2 u
= 8 u

8 u = 56

1 u = 56 ÷ 8 = 7

Number of fruits in Box V in the end
= 5 u + 10 u
= 15 u
= 15 x 7
= 105

Answer(s): 105