There were some mangoes and lemons in Box C and Box D. In Box C, the ratio of the mangoes to the number of lemons was 7 : 1. In Box D, the ratio of the number of mangoes to the number of lemons was 5 : 3. There were 3 times as many fruits in Box C as in Box D. After another 68 lemons were put into Box D, the ratio of the number of mangoes to the number of lemons in Box D became 1 : 4. How many fruits were there in Box C?
Box C |
Box D |
3x8 = 24 u |
1x8 = 8 u |
Mangoes |
Lemons |
Mangoes |
Lemons |
7x3 |
1x3 |
5 |
3 |
21 u |
3 u |
5 u |
3 u |
The total number of fruits in Box C is repeated. Make the total number of fruits in Box C the same. LCM of 3 and 8 is 24.
The total number of fruits in Box D at first is repeated. Make the total number of fruits in Box D the same. LCM of 1 and 8 is 8.
|
Box C |
Box D |
|
Mangoes |
Lemons |
Mangoes |
Lemons |
Before |
21 u |
3 u |
5 u |
3 u |
Change |
|
|
|
+ 68 |
After
|
21 u
|
3 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of mangoes in Box D remains unchanged. Make the number of mangoes in Box D the same. LCM of 5 and 1 is 5.
Number of lemons put into Box D
= 20 u - 3 u
= 17 u
17 u = 68
1 u = 68 ÷ 17 = 4
Number of fruits in Box C
= 21 u + 3 u
= 24 u
= 24 x 4
= 96
Answer(s): 96