There were some oranges and passion fruits in Container M and Container N. In Container M, the ratio of the oranges to the number of passion fruits was 3 : 1. In Container N, the ratio of the number of oranges to the number of passion fruits was 3 : 1. There were 3 times as many fruits in Container M as in Container N. After another 72 passion fruits were put into Container N, the ratio of the number of oranges to the number of passion fruits in Container N became 1 : 3. How many fruits were there in Container M?
Container M |
Container N |
3x4 = 12 u |
1x4 = 4 u |
Oranges |
Passion fruits |
Oranges |
Passion fruits |
3x3 |
1x3 |
3 |
1 |
9 u |
3 u |
3 u |
1 u |
The total number of fruits in Container M is repeated. Make the total number of fruits in Container M the same. LCM of 3 and 4 is 12.
The total number of fruits in Container N at first is repeated. Make the total number of fruits in Container N the same. LCM of 1 and 4 is 4.
|
Container M |
Container N |
|
Oranges |
Passion fruits |
Oranges |
Passion fruits |
Before |
9 u |
3 u |
3 u |
1 u |
Change |
|
|
|
+ 72 |
After
|
9 u
|
3 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of oranges in Container N remains unchanged. Make the number of oranges in Container N the same. LCM of 3 and 1 is 3.
Number of passion fruits put into Container N
= 9 u - 1 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of fruits in Container M
= 9 u + 3 u
= 12 u
= 12 x 9
= 108
Answer(s): 108