There were some pears and starfruits in Container S and Container T. In Container S, the ratio of the pears to the number of starfruits was 4 : 1. In Container T, the ratio of the number of pears to the number of starfruits was 3 : 2. There were 2 times as many fruits in Container S as in Container T. After another 14 starfruits were put into Container T, the ratio of the number of pears to the number of starfruits in Container T became 1 : 3. How many fruits were there in Container S?

Container S		Container T
2x5 = 10 u		1x5 = 5 u
Pears	Starfruits	Pears	Starfruits
4x2	1x2	3	2
8 u	2 u	3 u	2 u

The total number of fruits in Container S is repeated.  Make the total number of fruits in Container S the same.  LCM of 2 and 5 is 10.

The total number of fruits in Container T at first is repeated.  Make the total number of fruits in Container T the same.  LCM of 1 and 5 is 5.

	Container S		Container T
	Pears	Starfruits	Pears	Starfruits
Before	8 u	2 u	3 u	2 u
Change				+ 14
After	8 u	2 u	1x3 = 3 u	3x3 = 9 u

Number of pears in Container T remains unchanged.  Make the number of pears in Container T the same.  LCM of 3 and 1 is 3.

Number of starfruits put into Container T
= 9 u - 2 u
= 7 u

7 u = 14

1 u = 14 ÷ 7 = 2

Number of fruits in Container S
= 8 u + 2 u
= 10 u
= 10 x 2
= 20

Answer(s): 20