There were some oranges and mangosteens in Box J and Box K. In Box J, the ratio of the oranges to the number of mangosteens was 4 : 1. In Box K, the ratio of the number of oranges to the number of mangosteens was 3 : 2. There were 3 times as many fruits in Box J as in Box K. After another 40 mangosteens were put into Box K, the ratio of the number of oranges to the number of mangosteens in Box K became 1 : 4. How many fruits were there in Box J?
Box J |
Box K |
3x5 = 15 u |
1x5 = 5 u |
Oranges |
Mangosteens |
Oranges |
Mangosteens |
4x3 |
1x3 |
3 |
2 |
12 u |
3 u |
3 u |
2 u |
The total number of fruits in Box J is repeated. Make the total number of fruits in Box J the same. LCM of 3 and 5 is 15.
The total number of fruits in Box K at first is repeated. Make the total number of fruits in Box K the same. LCM of 1 and 5 is 5.
|
Box J |
Box K |
|
Oranges |
Mangosteens |
Oranges |
Mangosteens |
Before |
12 u |
3 u |
3 u |
2 u |
Change |
|
|
|
+ 40 |
After
|
12 u
|
3 u
|
1x3 = 3 u |
4x3 = 12 u |
Number of oranges in Box K remains unchanged. Make the number of oranges in Box K the same. LCM of 3 and 1 is 3.
Number of mangosteens put into Box K
= 12 u - 2 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of fruits in Box J
= 12 u + 3 u
= 15 u
= 15 x 4
= 60
Answer(s): 60