There were some chikoos and kiwis in Container G and Container H. In Container G, the ratio of the chikoos to the number of kiwis was 7 : 1. In Container H, the ratio of the number of chikoos to the number of kiwis was 5 : 3. There were 2 times as many fruits in Container G as in Container H. After another 85 kiwis were put into Container H, the ratio of the number of chikoos to the number of kiwis in Container H became 1 : 4. How many fruits were there in Container H in the end?
Container G |
Container H |
2x8 = 16 u |
1x8 = 8 u |
Chikoos |
Kiwis |
Chikoos |
Kiwis |
7x2 |
1x2 |
5 |
3 |
14 u |
2 u |
5 u |
3 u |
The total number of fruits in Container G is repeated. Make the total number of fruits in Container G the same. LCM of 2 and 8 is 16.
The total number of fruits in Container H at first is repeated. Make the total number of fruits in Container H the same. LCM of 1 and 8 is 8.
|
Container G |
Container H |
|
Chikoos |
Kiwis |
Chikoos |
Kiwis |
Before |
14 u |
2 u |
5 u |
3 u |
Change |
|
|
|
+ 85 |
After
|
14 u
|
2 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of chikoos in Container H remains unchanged. Make the number of chikoos in Container H the same. LCM of 5 and 1 is 5.
Number of kiwis put into Container H
= 20 u - 3 u
= 17 u
17 u = 85
1 u = 85 ÷ 17 = 5
Number of fruits in Container H in the end
= 5 u + 20 u
= 25 u
= 25 x 5
= 125
Answer(s): 125