There were some persimmons and mangosteens in Container T and Container U. In Container T, the ratio of the persimmons to the number of mangosteens was 7 : 1. In Container U, the ratio of the number of persimmons to the number of mangosteens was 5 : 3. There were 2 times as many fruits in Container T as in Container U. After another 21 mangosteens were put into Container U, the ratio of the number of persimmons to the number of mangosteens in Container U became 1 : 2. How many fruits were there in Container T?

Container T		Container U
2x8 = 16 u		1x8 = 8 u
Persimmons	Mangosteens	Persimmons	Mangosteens
7x2	1x2	5	3
14 u	2 u	5 u	3 u

The total number of fruits in Container T is repeated.  Make the total number of fruits in Container T the same.  LCM of 2 and 8 is 16.

The total number of fruits in Container U at first is repeated.  Make the total number of fruits in Container U the same.  LCM of 1 and 8 is 8.

	Container T		Container U
	Persimmons	Mangosteens	Persimmons	Mangosteens
Before	14 u	2 u	5 u	3 u
Change				+ 21
After	14 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of persimmons in Container U remains unchanged.  Make the number of persimmons in Container U the same.  LCM of 5 and 1 is 5.

Number of mangosteens put into Container U
= 10 u - 3 u
= 7 u

7 u = 21

1 u = 21 ÷ 7 = 3

Number of fruits in Container T
= 14 u + 2 u
= 16 u
= 16 x 3
= 48

Answer(s): 48