There were some lemons and mangosteens in Container V and Container W. In Container V, the ratio of the lemons to the number of mangosteens was 3 : 1. In Container W, the ratio of the number of lemons to the number of mangosteens was 3 : 1. There were 2 times as many fruits in Container V as in Container W. After another 35 mangosteens were put into Container W, the ratio of the number of lemons to the number of mangosteens in Container W became 1 : 2. How many fruits were there in Container V?
Container V |
Container W |
2x4 = 8 u |
1x4 = 4 u |
Lemons |
Mangosteens |
Lemons |
Mangosteens |
3x2 |
1x2 |
3 |
1 |
6 u |
2 u |
3 u |
1 u |
The total number of fruits in Container V is repeated. Make the total number of fruits in Container V the same. LCM of 2 and 4 is 8.
The total number of fruits in Container W at first is repeated. Make the total number of fruits in Container W the same. LCM of 1 and 4 is 4.
|
Container V |
Container W |
|
Lemons |
Mangosteens |
Lemons |
Mangosteens |
Before |
6 u |
2 u |
3 u |
1 u |
Change |
|
|
|
+ 35 |
After
|
6 u
|
2 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of lemons in Container W remains unchanged. Make the number of lemons in Container W the same. LCM of 3 and 1 is 3.
Number of mangosteens put into Container W
= 6 u - 1 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of fruits in Container V
= 6 u + 2 u
= 8 u
= 8 x 7
= 56
Answer(s): 56