There were some mangosteens and pomegranates in Container C and Container D. In Container C, the ratio of the mangosteens to the number of pomegranates was 4 : 1. In Container D, the ratio of the number of mangosteens to the number of pomegranates was 3 : 2. There were 2 times as many fruits in Container C as in Container D. After another 24 pomegranates were put into Container D, the ratio of the number of mangosteens to the number of pomegranates in Container D became 1 : 2. How many fruits were there in Container D in the end?
Container C |
Container D |
2x5 = 10 u |
1x5 = 5 u |
Mangosteens |
Pomegranates |
Mangosteens |
Pomegranates |
4x2 |
1x2 |
3 |
2 |
8 u |
2 u |
3 u |
2 u |
The total number of fruits in Container C is repeated. Make the total number of fruits in Container C the same. LCM of 2 and 5 is 10.
The total number of fruits in Container D at first is repeated. Make the total number of fruits in Container D the same. LCM of 1 and 5 is 5.
|
Container C |
Container D |
|
Mangosteens |
Pomegranates |
Mangosteens |
Pomegranates |
Before |
8 u |
2 u |
3 u |
2 u |
Change |
|
|
|
+ 24 |
After
|
8 u
|
2 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of mangosteens in Container D remains unchanged. Make the number of mangosteens in Container D the same. LCM of 3 and 1 is 3.
Number of pomegranates put into Container D
= 6 u - 2 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of fruits in Container D in the end
= 3 u + 6 u
= 9 u
= 9 x 6
= 54
Answer(s): 54