There were some apples and pears in Container T and Container U. In Container T, the ratio of the apples to the number of pears was 6 : 1. In Container U, the ratio of the number of apples to the number of pears was 4 : 3. There were 3 times as many fruits in Container T as in Container U. After another 15 pears were put into Container U, the ratio of the number of apples to the number of pears in Container U became 1 : 2. How many fruits were there in Container T?

Container T		Container U
3x7 = 21 u		1x7 = 7 u
Apples	Pears	Apples	Pears
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container T is repeated.  Make the total number of fruits in Container T the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container U at first is repeated.  Make the total number of fruits in Container U the same.  LCM of 1 and 7 is 7.

	Container T		Container U
	Apples	Pears	Apples	Pears
Before	18 u	3 u	4 u	3 u
Change				+ 15
After	18 u	3 u	1x4 = 4 u	2x4 = 8 u

Number of apples in Container U remains unchanged.  Make the number of apples in Container U the same.  LCM of 4 and 1 is 4.

Number of pears put into Container U
= 8 u - 3 u
= 5 u

5 u = 15

1 u = 15 ÷ 5 = 3

Number of fruits in Container T
= 18 u + 3 u
= 21 u
= 21 x 3
= 63

Answer(s): 63