There were some mangoes and persimmons in Box X and Box Y. In Box X, the ratio of the mangoes to the number of persimmons was 6 : 1. In Box Y, the ratio of the number of mangoes to the number of persimmons was 5 : 2. There were 3 times as many fruits in Box X as in Box Y. After another 39 persimmons were put into Box Y, the ratio of the number of mangoes to the number of persimmons in Box Y became 1 : 3. How many fruits were there in Box X?
Box X |
Box Y |
3x7 = 21 u |
1x7 = 7 u |
Mangoes |
Persimmons |
Mangoes |
Persimmons |
6x3 |
1x3 |
5 |
2 |
18 u |
3 u |
5 u |
2 u |
The total number of fruits in Box X is repeated. Make the total number of fruits in Box X the same. LCM of 3 and 7 is 21.
The total number of fruits in Box Y at first is repeated. Make the total number of fruits in Box Y the same. LCM of 1 and 7 is 7.
|
Box X |
Box Y |
|
Mangoes |
Persimmons |
Mangoes |
Persimmons |
Before |
18 u |
3 u |
5 u |
2 u |
Change |
|
|
|
+ 39 |
After
|
18 u
|
3 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of mangoes in Box Y remains unchanged. Make the number of mangoes in Box Y the same. LCM of 5 and 1 is 5.
Number of persimmons put into Box Y
= 15 u - 2 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of fruits in Box X
= 18 u + 3 u
= 21 u
= 21 x 3
= 63
Answer(s): 63