There were some apples and mangoes in Box L and Box M. In Box L, the ratio of the apples to the number of mangoes was 4 : 1. In Box M, the ratio of the number of apples to the number of mangoes was 3 : 2. There were 3 times as many fruits in Box L as in Box M. After another 49 mangoes were put into Box M, the ratio of the number of apples to the number of mangoes in Box M became 1 : 3. How many fruits were there in Box L?
| Box L |
Box M |
3x5 =
15 u |
1x5 =
5 u |
| Apples |
Mangoes |
Apples |
Mangoes |
| 4x3 |
1x3 |
3 |
2 |
| 12 u |
3 u |
3 u |
2 u |
The total number of fruits in Box L is repeated. Make the total number of fruits in Box L the same. LCM of 3 and 5 is 15.
The total number of fruits in Box M at first is repeated. Make the total number of fruits in Box M the same. LCM of 1 and 5 is 5.
| |
Box L |
Box M |
| |
Apples |
Mangoes |
Apples |
Mangoes |
| Before |
12 u |
3 u |
3 u |
2 u |
| Change |
|
|
|
+ 49 |
After
|
12 u
|
3 u
|
1x3 =
3 u |
3x3 =
9 u |
Number of apples in Box M remains unchanged. Make the number of apples in Box M the same. LCM of 3 and 1 is 3.
Number of mangoes put into Box M
= 9 u - 2 u
= 7 u
7 u = 49
1 u = 49 ÷ 7 = 7
Number of fruits in Box L
= 12 u + 3 u
= 15 u
= 15 x 7
= 105
Answer(s): 105
