There were some lemons and kiwis in Container P and Container Q. In Container P, the ratio of the lemons to the number of kiwis was 6 : 1. In Container Q, the ratio of the number of lemons to the number of kiwis was 4 : 3. There were 2 times as many fruits in Container P as in Container Q. After another 54 kiwis were put into Container Q, the ratio of the number of lemons to the number of kiwis in Container Q became 1 : 3. How many fruits were there in Container Q in the end?

Container P		Container Q
2x7 = 14 u		1x7 = 7 u
Lemons	Kiwis	Lemons	Kiwis
6x2	1x2	4	3
12 u	2 u	4 u	3 u

The total number of fruits in Container P is repeated.  Make the total number of fruits in Container P the same.  LCM of 2 and 7 is 14.

The total number of fruits in Container Q at first is repeated.  Make the total number of fruits in Container Q the same.  LCM of 1 and 7 is 7.

	Container P		Container Q
	Lemons	Kiwis	Lemons	Kiwis
Before	12 u	2 u	4 u	3 u
Change				+ 54
After	12 u	2 u	1x4 = 4 u	3x4 = 12 u

Number of lemons in Container Q remains unchanged.  Make the number of lemons in Container Q the same.  LCM of 4 and 1 is 4.

Number of kiwis put into Container Q
= 12 u - 3 u
= 9 u

9 u = 54

1 u = 54 ÷ 9 = 6

Number of fruits in Container Q in the end
= 4 u + 12 u
= 16 u
= 16 x 6
= 96

Answer(s): 96