There were some starfruits and oranges in Box T and Box U. In Box T, the ratio of the starfruits to the number of oranges was 5 : 1. In Box U, the ratio of the number of starfruits to the number of oranges was 5 : 3. There were 3 times as many fruits in Box T as in Box U. After another 120 oranges were put into Box U, the ratio of the number of starfruits to the number of oranges in Box U became 1 : 3. How many fruits were there in Box T?
Box T |
Box U |
3x8 = 24 u |
1x8 = 8 u |
Starfruits |
Oranges |
Starfruits |
Oranges |
5x4 |
1x4 |
5 |
3 |
20 u |
4 u |
5 u |
3 u |
The total number of fruits in Box T is repeated. Make the total number of fruits in Box T the same. LCM of 3 and 6 is 24.
The total number of fruits in Box U at first is repeated. Make the total number of fruits in Box U the same. LCM of 1 and 8 is 8.
|
Box T |
Box U |
|
Starfruits |
Oranges |
Starfruits |
Oranges |
Before |
20 u |
4 u |
5 u |
3 u |
Change |
|
|
|
+ 120 |
After
|
20 u
|
4 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of starfruits in Box U remains unchanged. Make the number of starfruits in Box U the same. LCM of 5 and 1 is 5.
Number of oranges put into Box U
= 15 u - 3 u
= 12 u
12 u = 120
1 u = 120 ÷ 12 = 10
Number of fruits in Box T
= 20 u + 4 u
= 24 u
= 24 x 10
= 240
Answer(s): 240