There were some oranges and mangosteens in Box X and Box Y. In Box X, the ratio of the oranges to the number of mangosteens was 11 : 1. In Box Y, the ratio of the number of oranges to the number of mangosteens was 5 : 3. There were 3 times as many fruits in Box X as in Box Y. After another 60 mangosteens were put into Box Y, the ratio of the number of oranges to the number of mangosteens in Box Y became 1 : 3. How many fruits were there in Box Y in the end?
Box X |
Box Y |
3x8 = 24 u |
1x8 = 8 u |
Oranges |
Mangosteens |
Oranges |
Mangosteens |
11x2 |
1x2 |
5 |
3 |
22 u |
2 u |
5 u |
3 u |
The total number of fruits in Box X is repeated. Make the total number of fruits in Box X the same. LCM of 3 and 12 is 24.
The total number of fruits in Box Y at first is repeated. Make the total number of fruits in Box Y the same. LCM of 1 and 8 is 8.
|
Box X |
Box Y |
|
Oranges |
Mangosteens |
Oranges |
Mangosteens |
Before |
22 u |
2 u |
5 u |
3 u |
Change |
|
|
|
+ 60 |
After
|
22 u
|
2 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of oranges in Box Y remains unchanged. Make the number of oranges in Box Y the same. LCM of 5 and 1 is 5.
Number of mangosteens put into Box Y
= 15 u - 3 u
= 12 u
12 u = 60
1 u = 60 ÷ 12 = 5
Number of fruits in Box Y in the end
= 5 u + 15 u
= 20 u
= 20 x 5
= 100
Answer(s): 100