There were some apples and mangoes in Container H and Container J. In Container H, the ratio of the apples to the number of mangoes was 4 : 1. In Container J, the ratio of the number of apples to the number of mangoes was 3 : 2. There were 3 times as many fruits in Container H as in Container J. After another 35 mangoes were put into Container J, the ratio of the number of apples to the number of mangoes in Container J became 1 : 3. How many fruits were there in Container J in the end?

Container H		Container J
3x5 = 15 u		1x5 = 5 u
Apples	Mangoes	Apples	Mangoes
4x3	1x3	3	2
12 u	3 u	3 u	2 u

The total number of fruits in Container H is repeated.  Make the total number of fruits in Container H the same.  LCM of 3 and 5 is 15.

The total number of fruits in Container J at first is repeated.  Make the total number of fruits in Container J the same.  LCM of 1 and 5 is 5.

	Container H		Container J
	Apples	Mangoes	Apples	Mangoes
Before	12 u	3 u	3 u	2 u
Change				+ 35
After	12 u	3 u	1x3 = 3 u	3x3 = 9 u

Number of apples in Container J remains unchanged.  Make the number of apples in Container J the same.  LCM of 3 and 1 is 3.

Number of mangoes put into Container J
= 9 u - 2 u
= 7 u

7 u = 35

1 u = 35 ÷ 7 = 5

Number of fruits in Container J in the end
= 3 u + 9 u
= 12 u
= 12 x 5
= 60

Answer(s): 60