There were some pears and mangosteens in Container B and Container C. In Container B, the ratio of the pears to the number of mangosteens was 4 : 1. In Container C, the ratio of the number of pears to the number of mangosteens was 3 : 2. There were 2 times as many fruits in Container B as in Container C. After another 40 mangosteens were put into Container C, the ratio of the number of pears to the number of mangosteens in Container C became 1 : 2. How many fruits were there in Container C in the end?

Container B		Container C
2x5 = 10 u		1x5 = 5 u
Pears	Mangosteens	Pears	Mangosteens
4x2	1x2	3	2
8 u	2 u	3 u	2 u

The total number of fruits in Container B is repeated.  Make the total number of fruits in Container B the same.  LCM of 2 and 5 is 10.

The total number of fruits in Container C at first is repeated.  Make the total number of fruits in Container C the same.  LCM of 1 and 5 is 5.

	Container B		Container C
	Pears	Mangosteens	Pears	Mangosteens
Before	8 u	2 u	3 u	2 u
Change				+ 40
After	8 u	2 u	1x3 = 3 u	2x3 = 6 u

Number of pears in Container C remains unchanged.  Make the number of pears in Container C the same.  LCM of 3 and 1 is 3.

Number of mangosteens put into Container C
= 6 u - 2 u
= 4 u

4 u = 40

1 u = 40 ÷ 4 = 10

Number of fruits in Container C in the end
= 3 u + 6 u
= 9 u
= 9 x 10
= 90

Answer(s): 90