There were some persimmons and apples in Box W and Box X. In Box W, the ratio of the persimmons to the number of apples was 1 : 1. In Box X, the ratio of the number of persimmons to the number of apples was 3 : 1. There were 2 times as many fruits in Box W as in Box X. After another 45 apples were put into Box X, the ratio of the number of persimmons to the number of apples in Box X became 1 : 2. How many fruits were there in Box W?
Box W |
Box X |
2x4 = 8 u |
1x4 = 4 u |
Persimmons |
Apples |
Persimmons |
Apples |
1x4 |
1x4 |
3 |
1 |
4 u |
4 u |
3 u |
1 u |
The total number of fruits in Box W is repeated. Make the total number of fruits in Box W the same. LCM of 2 and 2 is 8.
The total number of fruits in Box X at first is repeated. Make the total number of fruits in Box X the same. LCM of 1 and 4 is 4.
|
Box W |
Box X |
|
Persimmons |
Apples |
Persimmons |
Apples |
Before |
4 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 45 |
After
|
4 u
|
4 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of persimmons in Box X remains unchanged. Make the number of persimmons in Box X the same. LCM of 3 and 1 is 3.
Number of apples put into Box X
= 6 u - 1 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of fruits in Box W
= 4 u + 4 u
= 8 u
= 8 x 9
= 72
Answer(s): 72