There were some pomegranates and kiwis in Container M and Container N. In Container M, the ratio of the pomegranates to the number of kiwis was 5 : 1. In Container N, the ratio of the number of pomegranates to the number of kiwis was 5 : 3. There were 3 times as many fruits in Container M as in Container N. After another 96 kiwis were put into Container N, the ratio of the number of pomegranates to the number of kiwis in Container N became 1 : 3. How many fruits were there in Container M?

Container M		Container N
3x8 = 24 u		1x8 = 8 u
Pomegranates	Kiwis	Pomegranates	Kiwis
5x4	1x4	5	3
20 u	4 u	5 u	3 u

The total number of fruits in Container M is repeated.  Make the total number of fruits in Container M the same.  LCM of 3 and 6 is 24.

The total number of fruits in Container N at first is repeated.  Make the total number of fruits in Container N the same.  LCM of 1 and 8 is 8.

	Container M		Container N
	Pomegranates	Kiwis	Pomegranates	Kiwis
Before	20 u	4 u	5 u	3 u
Change				+ 96
After	20 u	4 u	1x5 = 5 u	3x5 = 15 u

Number of pomegranates in Container N remains unchanged.  Make the number of pomegranates in Container N the same.  LCM of 5 and 1 is 5.

Number of kiwis put into Container N
= 15 u - 3 u
= 12 u

12 u = 96

1 u = 96 ÷ 12 = 8

Number of fruits in Container M
= 20 u + 4 u
= 24 u
= 24 x 8
= 192

Answer(s): 192