There were some mangoes and persimmons in Container S and Container T. In Container S, the ratio of the mangoes to the number of persimmons was 1 : 1. In Container T, the ratio of the number of mangoes to the number of persimmons was 3 : 1. There were 2 times as many fruits in Container S as in Container T. After another 35 persimmons were put into Container T, the ratio of the number of mangoes to the number of persimmons in Container T became 1 : 2. How many fruits were there in Container S?

Container S		Container T
2x4 = 8 u		1x4 = 4 u
Mangoes	Persimmons	Mangoes	Persimmons
1x4	1x4	3	1
4 u	4 u	3 u	1 u

The total number of fruits in Container S is repeated.  Make the total number of fruits in Container S the same.  LCM of 2 and 2 is 8.

The total number of fruits in Container T at first is repeated.  Make the total number of fruits in Container T the same.  LCM of 1 and 4 is 4.

	Container S		Container T
	Mangoes	Persimmons	Mangoes	Persimmons
Before	4 u	4 u	3 u	1 u
Change				+ 35
After	4 u	4 u	1x3 = 3 u	2x3 = 6 u

Number of mangoes in Container T remains unchanged.  Make the number of mangoes in Container T the same.  LCM of 3 and 1 is 3.

Number of persimmons put into Container T
= 6 u - 1 u
= 5 u

5 u = 35

1 u = 35 ÷ 5 = 7

Number of fruits in Container S
= 4 u + 4 u
= 8 u
= 8 x 7
= 56

Answer(s): 56