There were some pears and mangoes in Container C and Container D. In Container C, the ratio of the pears to the number of mangoes was 7 : 1. In Container D, the ratio of the number of pears to the number of mangoes was 5 : 3. There were 3 times as many fruits in Container C as in Container D. After another 28 mangoes were put into Container D, the ratio of the number of pears to the number of mangoes in Container D became 1 : 2. How many fruits were there in Container C?

Container C		Container D
3x8 = 24 u		1x8 = 8 u
Pears	Mangoes	Pears	Mangoes
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Container C is repeated.  Make the total number of fruits in Container C the same.  LCM of 3 and 8 is 24.

The total number of fruits in Container D at first is repeated.  Make the total number of fruits in Container D the same.  LCM of 1 and 8 is 8.

	Container C		Container D
	Pears	Mangoes	Pears	Mangoes
Before	21 u	3 u	5 u	3 u
Change				+ 28
After	21 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of pears in Container D remains unchanged.  Make the number of pears in Container D the same.  LCM of 5 and 1 is 5.

Number of mangoes put into Container D
= 10 u - 3 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of fruits in Container C
= 21 u + 3 u
= 24 u
= 24 x 4
= 96

Answer(s): 96