There were some lemons and pomegranates in Box J and Box K. In Box J, the ratio of the lemons to the number of pomegranates was 6 : 1. In Box K, the ratio of the number of lemons to the number of pomegranates was 5 : 2. There were 2 times as many fruits in Box J as in Box K. After another 144 pomegranates were put into Box K, the ratio of the number of lemons to the number of pomegranates in Box K became 1 : 4. How many fruits were there in Box K in the end?
Box J |
Box K |
2x7 = 14 u |
1x7 = 7 u |
Lemons |
Pomegranates |
Lemons |
Pomegranates |
6x2 |
1x2 |
5 |
2 |
12 u |
2 u |
5 u |
2 u |
The total number of fruits in Box J is repeated. Make the total number of fruits in Box J the same. LCM of 2 and 7 is 14.
The total number of fruits in Box K at first is repeated. Make the total number of fruits in Box K the same. LCM of 1 and 7 is 7.
|
Box J |
Box K |
|
Lemons |
Pomegranates |
Lemons |
Pomegranates |
Before |
12 u |
2 u |
5 u |
2 u |
Change |
|
|
|
+ 144 |
After
|
12 u
|
2 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of lemons in Box K remains unchanged. Make the number of lemons in Box K the same. LCM of 5 and 1 is 5.
Number of pomegranates put into Box K
= 20 u - 2 u
= 18 u
18 u = 144
1 u = 144 ÷ 18 = 8
Number of fruits in Box K in the end
= 5 u + 20 u
= 25 u
= 25 x 8
= 200
Answer(s): 200