There were some mangoes and pomegranates in Box Y and Box Z. In Box Y, the ratio of the mangoes to the number of pomegranates was 3 : 1. In Box Z, the ratio of the number of mangoes to the number of pomegranates was 3 : 1. There were 2 times as many fruits in Box Y as in Box Z. After another 80 pomegranates were put into Box Z, the ratio of the number of mangoes to the number of pomegranates in Box Z became 1 : 3. How many fruits were there in Box Y?

Box Y		Box Z
2x4 = 8 u		1x4 = 4 u
Mangoes	Pomegranates	Mangoes	Pomegranates
3x2	1x2	3	1
6 u	2 u	3 u	1 u

The total number of fruits in Box Y is repeated.  Make the total number of fruits in Box Y the same.  LCM of 2 and 4 is 8.

The total number of fruits in Box Z at first is repeated.  Make the total number of fruits in Box Z the same.  LCM of 1 and 4 is 4.

	Box Y		Box Z
	Mangoes	Pomegranates	Mangoes	Pomegranates
Before	6 u	2 u	3 u	1 u
Change				+ 80
After	6 u	2 u	1x3 = 3 u	3x3 = 9 u

Number of mangoes in Box Z remains unchanged.  Make the number of mangoes in Box Z the same.  LCM of 3 and 1 is 3.

Number of pomegranates put into Box Z
= 9 u - 1 u
= 8 u

8 u = 80

1 u = 80 ÷ 8 = 10

Number of fruits in Box Y
= 6 u + 2 u
= 8 u
= 8 x 10
= 80

Answer(s): 80