There were some starfruits and chikoos in Container Q and Container R. In Container Q, the ratio of the starfruits to the number of chikoos was 6 : 1. In Container R, the ratio of the number of starfruits to the number of chikoos was 4 : 3. There were 3 times as many fruits in Container Q as in Container R. After another 20 chikoos were put into Container R, the ratio of the number of starfruits to the number of chikoos in Container R became 1 : 2. How many fruits were there in Container R in the end?

Container Q		Container R
3x7 = 21 u		1x7 = 7 u
Starfruits	Chikoos	Starfruits	Chikoos
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container Q is repeated.  Make the total number of fruits in Container Q the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container R at first is repeated.  Make the total number of fruits in Container R the same.  LCM of 1 and 7 is 7.

	Container Q		Container R
	Starfruits	Chikoos	Starfruits	Chikoos
Before	18 u	3 u	4 u	3 u
Change				+ 20
After	18 u	3 u	1x4 = 4 u	2x4 = 8 u

Number of starfruits in Container R remains unchanged.  Make the number of starfruits in Container R the same.  LCM of 4 and 1 is 4.

Number of chikoos put into Container R
= 8 u - 3 u
= 5 u

5 u = 20

1 u = 20 ÷ 5 = 4

Number of fruits in Container R in the end
= 4 u + 8 u
= 12 u
= 12 x 4
= 48

Answer(s): 48