There were some starfruits and lemons in Container E and Container F. In Container E, the ratio of the starfruits to the number of lemons was 7 : 1. In Container F, the ratio of the number of starfruits to the number of lemons was 5 : 3. There were 2 times as many fruits in Container E as in Container F. After another 48 lemons were put into Container F, the ratio of the number of starfruits to the number of lemons in Container F became 1 : 3. How many fruits were there in Container E?

Container E		Container F
2x8 = 16 u		1x8 = 8 u
Starfruits	Lemons	Starfruits	Lemons
7x2	1x2	5	3
14 u	2 u	5 u	3 u

The total number of fruits in Container E is repeated.  Make the total number of fruits in Container E the same.  LCM of 2 and 8 is 16.

The total number of fruits in Container F at first is repeated.  Make the total number of fruits in Container F the same.  LCM of 1 and 8 is 8.

	Container E		Container F
	Starfruits	Lemons	Starfruits	Lemons
Before	14 u	2 u	5 u	3 u
Change				+ 48
After	14 u	2 u	1x5 = 5 u	3x5 = 15 u

Number of starfruits in Container F remains unchanged.  Make the number of starfruits in Container F the same.  LCM of 5 and 1 is 5.

Number of lemons put into Container F
= 15 u - 3 u
= 12 u

12 u = 48

1 u = 48 ÷ 12 = 4

Number of fruits in Container E
= 14 u + 2 u
= 16 u
= 16 x 4
= 64

Answer(s): 64