There were some persimmons and kiwis in Box G and Box H. In Box G, the ratio of the persimmons to the number of kiwis was 3 : 1. In Box H, the ratio of the number of persimmons to the number of kiwis was 3 : 1. There were 2 times as many fruits in Box G as in Box H. After another 24 kiwis were put into Box H, the ratio of the number of persimmons to the number of kiwis in Box H became 1 : 3. How many fruits were there in Box G?
Box G |
Box H |
2x4 = 8 u |
1x4 = 4 u |
Persimmons |
Kiwis |
Persimmons |
Kiwis |
3x2 |
1x2 |
3 |
1 |
6 u |
2 u |
3 u |
1 u |
The total number of fruits in Box G is repeated. Make the total number of fruits in Box G the same. LCM of 2 and 4 is 8.
The total number of fruits in Box H at first is repeated. Make the total number of fruits in Box H the same. LCM of 1 and 4 is 4.
|
Box G |
Box H |
|
Persimmons |
Kiwis |
Persimmons |
Kiwis |
Before |
6 u |
2 u |
3 u |
1 u |
Change |
|
|
|
+ 24 |
After
|
6 u
|
2 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of persimmons in Box H remains unchanged. Make the number of persimmons in Box H the same. LCM of 3 and 1 is 3.
Number of kiwis put into Box H
= 9 u - 1 u
= 8 u
8 u = 24
1 u = 24 ÷ 8 = 3
Number of fruits in Box G
= 6 u + 2 u
= 8 u
= 8 x 3
= 24
Answer(s): 24