There were some chikoos and apples in Box D and Box E. In Box D, the ratio of the chikoos to the number of apples was 7 : 1. In Box E, the ratio of the number of chikoos to the number of apples was 5 : 3. There were 3 times as many fruits in Box D as in Box E. After another 24 apples were put into Box E, the ratio of the number of chikoos to the number of apples in Box E became 1 : 3. How many fruits were there in Box E in the end?

Box D		Box E
3x8 = 24 u		1x8 = 8 u
Chikoos	Apples	Chikoos	Apples
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Box D is repeated.  Make the total number of fruits in Box D the same.  LCM of 3 and 8 is 24.

The total number of fruits in Box E at first is repeated.  Make the total number of fruits in Box E the same.  LCM of 1 and 8 is 8.

	Box D		Box E
	Chikoos	Apples	Chikoos	Apples
Before	21 u	3 u	5 u	3 u
Change				+ 24
After	21 u	3 u	1x5 = 5 u	3x5 = 15 u

Number of chikoos in Box E remains unchanged.  Make the number of chikoos in Box E the same.  LCM of 5 and 1 is 5.

Number of apples put into Box E
= 15 u - 3 u
= 12 u

12 u = 24

1 u = 24 ÷ 12 = 2

Number of fruits in Box E in the end
= 5 u + 15 u
= 20 u
= 20 x 2
= 40

Answer(s): 40