There were some apples and pears in Box P and Box Q. In Box P, the ratio of the apples to the number of pears was 6 : 1. In Box Q, the ratio of the number of apples to the number of pears was 4 : 3. There were 3 times as many fruits in Box P as in Box Q. After another 25 pears were put into Box Q, the ratio of the number of apples to the number of pears in Box Q became 1 : 2. How many fruits were there in Box P?
Box P |
Box Q |
3x7 = 21 u |
1x7 = 7 u |
Apples |
Pears |
Apples |
Pears |
6x3 |
1x3 |
4 |
3 |
18 u |
3 u |
4 u |
3 u |
The total number of fruits in Box P is repeated. Make the total number of fruits in Box P the same. LCM of 3 and 7 is 21.
The total number of fruits in Box Q at first is repeated. Make the total number of fruits in Box Q the same. LCM of 1 and 7 is 7.
|
Box P |
Box Q |
|
Apples |
Pears |
Apples |
Pears |
Before |
18 u |
3 u |
4 u |
3 u |
Change |
|
|
|
+ 25 |
After
|
18 u
|
3 u
|
1x4 = 4 u |
2x4 = 8 u |
Number of apples in Box Q remains unchanged. Make the number of apples in Box Q the same. LCM of 4 and 1 is 4.
Number of pears put into Box Q
= 8 u - 3 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of fruits in Box P
= 18 u + 3 u
= 21 u
= 21 x 5
= 105
Answer(s): 105