There were some pomegranates and oranges in Container H and Container J. In Container H, the ratio of the pomegranates to the number of oranges was 6 : 1. In Container J, the ratio of the number of pomegranates to the number of oranges was 4 : 3. There were 3 times as many fruits in Container H as in Container J. After another 52 oranges were put into Container J, the ratio of the number of pomegranates to the number of oranges in Container J became 1 : 4. How many fruits were there in Container J in the end?

Container H		Container J
3x7 = 21 u		1x7 = 7 u
Pomegranates	Oranges	Pomegranates	Oranges
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container H is repeated.  Make the total number of fruits in Container H the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container J at first is repeated.  Make the total number of fruits in Container J the same.  LCM of 1 and 7 is 7.

	Container H		Container J
	Pomegranates	Oranges	Pomegranates	Oranges
Before	18 u	3 u	4 u	3 u
Change				+ 52
After	18 u	3 u	1x4 = 4 u	4x4 = 16 u

Number of pomegranates in Container J remains unchanged.  Make the number of pomegranates in Container J the same.  LCM of 4 and 1 is 4.

Number of oranges put into Container J
= 16 u - 3 u
= 13 u

13 u = 52

1 u = 52 ÷ 13 = 4

Number of fruits in Container J in the end
= 4 u + 16 u
= 20 u
= 20 x 4
= 80

Answer(s): 80