There were some lemons and oranges in Box K and Box L. In Box K, the ratio of the lemons to the number of oranges was 2 : 1. In Box L, the ratio of the number of lemons to the number of oranges was 3 : 1. There were 3 times as many fruits in Box K as in Box L. After another 50 oranges were put into Box L, the ratio of the number of lemons to the number of oranges in Box L became 1 : 2. How many fruits were there in Box L in the end?
Box K |
Box L |
3x4 = 12 u |
1x4 = 4 u |
Lemons |
Oranges |
Lemons |
Oranges |
2x4 |
1x4 |
3 |
1 |
8 u |
4 u |
3 u |
1 u |
The total number of fruits in Box K is repeated. Make the total number of fruits in Box K the same. LCM of 3 and 3 is 12.
The total number of fruits in Box L at first is repeated. Make the total number of fruits in Box L the same. LCM of 1 and 4 is 4.
|
Box K |
Box L |
|
Lemons |
Oranges |
Lemons |
Oranges |
Before |
8 u |
4 u |
3 u |
1 u |
Change |
|
|
|
+ 50 |
After
|
8 u
|
4 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of lemons in Box L remains unchanged. Make the number of lemons in Box L the same. LCM of 3 and 1 is 3.
Number of oranges put into Box L
= 6 u - 1 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of fruits in Box L in the end
= 3 u + 6 u
= 9 u
= 9 x 10
= 90
Answer(s): 90