There were some mangoes and chikoos in Container J and Container K. In Container J, the ratio of the mangoes to the number of chikoos was 4 : 1. In Container K, the ratio of the number of mangoes to the number of chikoos was 3 : 2. There were 3 times as many fruits in Container J as in Container K. After another 14 chikoos were put into Container K, the ratio of the number of mangoes to the number of chikoos in Container K became 1 : 3. How many fruits were there in Container J?
Container J |
Container K |
3x5 = 15 u |
1x5 = 5 u |
Mangoes |
Chikoos |
Mangoes |
Chikoos |
4x3 |
1x3 |
3 |
2 |
12 u |
3 u |
3 u |
2 u |
The total number of fruits in Container J is repeated. Make the total number of fruits in Container J the same. LCM of 3 and 5 is 15.
The total number of fruits in Container K at first is repeated. Make the total number of fruits in Container K the same. LCM of 1 and 5 is 5.
|
Container J |
Container K |
|
Mangoes |
Chikoos |
Mangoes |
Chikoos |
Before |
12 u |
3 u |
3 u |
2 u |
Change |
|
|
|
+ 14 |
After
|
12 u
|
3 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of mangoes in Container K remains unchanged. Make the number of mangoes in Container K the same. LCM of 3 and 1 is 3.
Number of chikoos put into Container K
= 9 u - 2 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of fruits in Container J
= 12 u + 3 u
= 15 u
= 15 x 2
= 30
Answer(s): 30