There were some apples and mangoes in Container E and Container F. In Container E, the ratio of the apples to the number of mangoes was 6 : 1. In Container F, the ratio of the number of apples to the number of mangoes was 5 : 2. There were 3 times as many fruits in Container E as in Container F. After another 54 mangoes were put into Container F, the ratio of the number of apples to the number of mangoes in Container F became 1 : 4. How many fruits were there in Container F in the end?

Container E		Container F
3x7 = 21 u		1x7 = 7 u
Apples	Mangoes	Apples	Mangoes
6x3	1x3	5	2
18 u	3 u	5 u	2 u

The total number of fruits in Container E is repeated.  Make the total number of fruits in Container E the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container F at first is repeated.  Make the total number of fruits in Container F the same.  LCM of 1 and 7 is 7.

	Container E		Container F
	Apples	Mangoes	Apples	Mangoes
Before	18 u	3 u	5 u	2 u
Change				+ 54
After	18 u	3 u	1x5 = 5 u	4x5 = 20 u

Number of apples in Container F remains unchanged.  Make the number of apples in Container F the same.  LCM of 5 and 1 is 5.

Number of mangoes put into Container F
= 20 u - 2 u
= 18 u

18 u = 54

1 u = 54 ÷ 18 = 3

Number of fruits in Container F in the end
= 5 u + 20 u
= 25 u
= 25 x 3
= 75

Answer(s): 75