There were some lemons and mangosteens in Container C and Container D. In Container C, the ratio of the lemons to the number of mangosteens was 4 : 1. In Container D, the ratio of the number of lemons to the number of mangosteens was 3 : 2. There were 3 times as many fruits in Container C as in Container D. After another 70 mangosteens were put into Container D, the ratio of the number of lemons to the number of mangosteens in Container D became 1 : 4. How many fruits were there in Container D in the end?
Container C |
Container D |
3x5 = 15 u |
1x5 = 5 u |
Lemons |
Mangosteens |
Lemons |
Mangosteens |
4x3 |
1x3 |
3 |
2 |
12 u |
3 u |
3 u |
2 u |
The total number of fruits in Container C is repeated. Make the total number of fruits in Container C the same. LCM of 3 and 5 is 15.
The total number of fruits in Container D at first is repeated. Make the total number of fruits in Container D the same. LCM of 1 and 5 is 5.
|
Container C |
Container D |
|
Lemons |
Mangosteens |
Lemons |
Mangosteens |
Before |
12 u |
3 u |
3 u |
2 u |
Change |
|
|
|
+ 70 |
After
|
12 u
|
3 u
|
1x3 = 3 u |
4x3 = 12 u |
Number of lemons in Container D remains unchanged. Make the number of lemons in Container D the same. LCM of 3 and 1 is 3.
Number of mangosteens put into Container D
= 12 u - 2 u
= 10 u
10 u = 70
1 u = 70 ÷ 10 = 7
Number of fruits in Container D in the end
= 3 u + 12 u
= 15 u
= 15 x 7
= 105
Answer(s): 105