There were some chikoos and oranges in Container X and Container Y. In Container X, the ratio of the chikoos to the number of oranges was 7 : 1. In Container Y, the ratio of the number of chikoos to the number of oranges was 5 : 3. There were 2 times as many fruits in Container X as in Container Y. After another 56 oranges were put into Container Y, the ratio of the number of chikoos to the number of oranges in Container Y became 1 : 2. How many fruits were there in Container Y in the end?

Container X		Container Y
2x8 = 16 u		1x8 = 8 u
Chikoos	Oranges	Chikoos	Oranges
7x2	1x2	5	3
14 u	2 u	5 u	3 u

The total number of fruits in Container X is repeated.  Make the total number of fruits in Container X the same.  LCM of 2 and 8 is 16.

The total number of fruits in Container Y at first is repeated.  Make the total number of fruits in Container Y the same.  LCM of 1 and 8 is 8.

	Container X		Container Y
	Chikoos	Oranges	Chikoos	Oranges
Before	14 u	2 u	5 u	3 u
Change				+ 56
After	14 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of chikoos in Container Y remains unchanged.  Make the number of chikoos in Container Y the same.  LCM of 5 and 1 is 5.

Number of oranges put into Container Y
= 10 u - 3 u
= 7 u

7 u = 56

1 u = 56 ÷ 7 = 8

Number of fruits in Container Y in the end
= 5 u + 10 u
= 15 u
= 15 x 8
= 120

Answer(s): 120