There were some mangoes and chikoos in Box S and Box T. In Box S, the ratio of the mangoes to the number of chikoos was 3 : 1. In Box T, the ratio of the number of mangoes to the number of chikoos was 3 : 1. There were 3 times as many fruits in Box S as in Box T. After another 40 chikoos were put into Box T, the ratio of the number of mangoes to the number of chikoos in Box T became 1 : 2. How many fruits were there in Box S?

Box S		Box T
3x4 = 12 u		1x4 = 4 u
Mangoes	Chikoos	Mangoes	Chikoos
3x3	1x3	3	1
9 u	3 u	3 u	1 u

The total number of fruits in Box S is repeated.  Make the total number of fruits in Box S the same.  LCM of 3 and 4 is 12.

The total number of fruits in Box T at first is repeated.  Make the total number of fruits in Box T the same.  LCM of 1 and 4 is 4.

	Box S		Box T
	Mangoes	Chikoos	Mangoes	Chikoos
Before	9 u	3 u	3 u	1 u
Change				+ 40
After	9 u	3 u	1x3 = 3 u	2x3 = 6 u

Number of mangoes in Box T remains unchanged.  Make the number of mangoes in Box T the same.  LCM of 3 and 1 is 3.

Number of chikoos put into Box T
= 6 u - 1 u
= 5 u

5 u = 40

1 u = 40 ÷ 5 = 8

Number of fruits in Box S
= 9 u + 3 u
= 12 u
= 12 x 8
= 96

Answer(s): 96