There were some kiwis and persimmons in Container W and Container X. In Container W, the ratio of the kiwis to the number of persimmons was 4 : 1. In Container X, the ratio of the number of kiwis to the number of persimmons was 3 : 2. There were 2 times as many fruits in Container W as in Container X. After another 60 persimmons were put into Container X, the ratio of the number of kiwis to the number of persimmons in Container X became 1 : 4. How many fruits were there in Container W?

Container W		Container X
2x5 = 10 u		1x5 = 5 u
Kiwis	Persimmons	Kiwis	Persimmons
4x2	1x2	3	2
8 u	2 u	3 u	2 u

The total number of fruits in Container W is repeated.  Make the total number of fruits in Container W the same.  LCM of 2 and 5 is 10.

The total number of fruits in Container X at first is repeated.  Make the total number of fruits in Container X the same.  LCM of 1 and 5 is 5.

	Container W		Container X
	Kiwis	Persimmons	Kiwis	Persimmons
Before	8 u	2 u	3 u	2 u
Change				+ 60
After	8 u	2 u	1x3 = 3 u	4x3 = 12 u

Number of kiwis in Container X remains unchanged.  Make the number of kiwis in Container X the same.  LCM of 3 and 1 is 3.

Number of persimmons put into Container X
= 12 u - 2 u
= 10 u

10 u = 60

1 u = 60 ÷ 10 = 6

Number of fruits in Container W
= 8 u + 2 u
= 10 u
= 10 x 6
= 60

Answer(s): 60