There were some passion fruits and mangoes in Container J and Container K. In Container J, the ratio of the passion fruits to the number of mangoes was 5 : 1. In Container K, the ratio of the number of passion fruits to the number of mangoes was 3 : 1. There were 3 times as many fruits in Container J as in Container K. After another 40 mangoes were put into Container K, the ratio of the number of passion fruits to the number of mangoes in Container K became 1 : 2. How many fruits were there in Container K in the end?

Container J		Container K
3x4 = 12 u		1x4 = 4 u
Passion fruits	Mangoes	Passion fruits	Mangoes
5x2	1x2	3	1
10 u	2 u	3 u	1 u

The total number of fruits in Container J is repeated.  Make the total number of fruits in Container J the same.  LCM of 3 and 6 is 12.

The total number of fruits in Container K at first is repeated.  Make the total number of fruits in Container K the same.  LCM of 1 and 4 is 4.

	Container J		Container K
	Passion fruits	Mangoes	Passion fruits	Mangoes
Before	10 u	2 u	3 u	1 u
Change				+ 40
After	10 u	2 u	1x3 = 3 u	2x3 = 6 u

Number of passion fruits in Container K remains unchanged.  Make the number of passion fruits in Container K the same.  LCM of 3 and 1 is 3.

Number of mangoes put into Container K
= 6 u - 1 u
= 5 u

5 u = 40

1 u = 40 ÷ 5 = 8

Number of fruits in Container K in the end
= 3 u + 6 u
= 9 u
= 9 x 8
= 72

Answer(s): 72