There were some mangosteens and lemons in Box X and Box Y. In Box X, the ratio of the mangosteens to the number of lemons was 6 : 1. In Box Y, the ratio of the number of mangosteens to the number of lemons was 4 : 3. There were 3 times as many fruits in Box X as in Box Y. After another 63 lemons were put into Box Y, the ratio of the number of mangosteens to the number of lemons in Box Y became 1 : 3. How many fruits were there in Box X?
Box X |
Box Y |
3x7 = 21 u |
1x7 = 7 u |
Mangosteens |
Lemons |
Mangosteens |
Lemons |
6x3 |
1x3 |
4 |
3 |
18 u |
3 u |
4 u |
3 u |
The total number of fruits in Box X is repeated. Make the total number of fruits in Box X the same. LCM of 3 and 7 is 21.
The total number of fruits in Box Y at first is repeated. Make the total number of fruits in Box Y the same. LCM of 1 and 7 is 7.
|
Box X |
Box Y |
|
Mangosteens |
Lemons |
Mangosteens |
Lemons |
Before |
18 u |
3 u |
4 u |
3 u |
Change |
|
|
|
+ 63 |
After
|
18 u
|
3 u
|
1x4 = 4 u |
3x4 = 12 u |
Number of mangosteens in Box Y remains unchanged. Make the number of mangosteens in Box Y the same. LCM of 4 and 1 is 4.
Number of lemons put into Box Y
= 12 u - 3 u
= 9 u
9 u = 63
1 u = 63 ÷ 9 = 7
Number of fruits in Box X
= 18 u + 3 u
= 21 u
= 21 x 7
= 147
Answer(s): 147