There were some chikoos and kiwis in Box M and Box N. In Box M, the ratio of the chikoos to the number of kiwis was 1 : 1. In Box N, the ratio of the number of chikoos to the number of kiwis was 3 : 1. There were 2 times as many fruits in Box M as in Box N. After another 77 kiwis were put into Box N, the ratio of the number of chikoos to the number of kiwis in Box N became 1 : 4. How many fruits were there in Box N in the end?

Box M		Box N
2x4 = 8 u		1x4 = 4 u
Chikoos	Kiwis	Chikoos	Kiwis
1x4	1x4	3	1
4 u	4 u	3 u	1 u

The total number of fruits in Box M is repeated.  Make the total number of fruits in Box M the same.  LCM of 2 and 2 is 8.

The total number of fruits in Box N at first is repeated.  Make the total number of fruits in Box N the same.  LCM of 1 and 4 is 4.

	Box M		Box N
	Chikoos	Kiwis	Chikoos	Kiwis
Before	4 u	4 u	3 u	1 u
Change				+ 77
After	4 u	4 u	1x3 = 3 u	4x3 = 12 u

Number of chikoos in Box N remains unchanged.  Make the number of chikoos in Box N the same.  LCM of 3 and 1 is 3.

Number of kiwis put into Box N
= 12 u - 1 u
= 11 u

11 u = 77

1 u = 77 ÷ 11 = 7

Number of fruits in Box N in the end
= 3 u + 12 u
= 15 u
= 15 x 7
= 105

Answer(s): 105